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Normal Distribution and Z-Scores
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Discussion Assignment #7
1. If a distribution is normal with μ = 60 and σ = 15, what is the z-score of 75?
2. If a distribution is normal with μ = 60 and σ = 15, what is the z score of 40?
3. How can the normal distribution be used to test hypotheses about populations? Also, how might you surmise that you can use this logic to test a hypothesis such as caffeine improves memory in the caffeine study that I reference in my lectures?
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Discuss7
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Discuss7
The formula for calculating the z-score of any value is given by: Z = (X - μ)/ σ where X is the experimental result, μ is the mean value, and σ is the standard deviation. Consequently, if a distribution is normal with μ = 60 and σ = 15, the z-score of 75 is going to be ((75 – 60)/15) = 1. On the other hand, if a distribution is normal with μ = 60 and σ = 15, the z-score of 40 is going to be ((40 – 60)/15) = -1.3333. The norm...
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